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[wi] Bewijs: ln(ab) = ln(a) + ln(b)
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Log[ab] =
INT1ab (1/t) dt = INT1a (1/t) dt + INTaab (1/t) dt Substitueer in de tweede integraal: t = x/a dt = dx/a Grenzen: t = a -> x = 1 t = ab -> x = b Invullen: INTaab (1/t) dt = INT1b (a/x) dx/a = INT1b (1/x) dx Oftewel: INT1ab (1/t) dt = INT1a (1/t) dt + INT1b (1/x) dx Log[ab] = Log[a] + Log[b] |
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